# IMAGE PROCESSING

" Two roads diverged in a wood, and I,
I took the one less traveled by,
And that has made all the difference "-Robert Frost

### Image Rotation in MATLAB - Examples without imrotate function

 180 degree
We can develop our own code to rotate an Image.In this article, I have discussed about the built in functions and the code to rotate an image without using imrotate function. At the end of the article you can find the matlab code.  First I tried to rotate an Image by using built in functions in Matlab.

Matlab built_in function rot90(A,k) can be used to rotate images in 90 degrees.
Here is an example using rot90:  Assign K=1 for 90 degree, 2 for 180, 3 for 270 and 4 for 360.

figure,imshow(A);

R=rot90(A(:,:,1),1);
G=rot90(A(:,:,2),1);
B=rot90(A(:,:,3),1);

C(:,:,1)=rot90(A(:,:,1),1);
C(:,:,2)=rot90(A(:,:,2),1);
C(:,:,3)=rot90(A(:,:,3),1);

figure,imshow(C);

 90 degree

The output image will be rotated 90 degrees.

Another matlab built_in function flipud(A) can be used to rotate the image 90 degrees. The actual function of flipud is to flip matrix up and down.

C=uint8(zeros(size(A)));
imshow(A);

R=flipud(A(:,:,1));
G=flipud(A(:,:,2));
B=flipud(A(:,:,3));

C(:,:,1)=R;
C(:,:,2)=G;
C(:,:,3)=B;

imshow(C);

 180 degree

To flip the image from left to right we can use the function fliplr

 Original Image

C=uint8(zeros(size(A)));
imshow(A);

R=fliplr(A(:,:,1));
G=fliplr(A(:,:,2));
B=fliplr(A(:,:,3));

C(:,:,1)=R;
C(:,:,2)=G;
C(:,:,3)=B;

imshow(C);

We can combine both fliplr and flipud to rotate the image (90, 180 , 270 and 360)

Now let’s see how to rotate an image without using matlab built in function imrotate.

Steps to be performed:

a.     Find the midpoints of the image.
b.     Convert the each pixel co-ordinate to polar co-ordinate.
c.      The result of conversion will yield angle and radius.
d.     Convert the angle which is in radians into degree by using the function rad2deg(theta)
e.      Add the degree value to be rotated to the value obtained in the above step.
f.       Now again convert the degree to radian by using rad2deg function
g.     Finally, convert to Cartesian co-ordinate by using the function pol2cart (theta,radius)

MATLAB CODE:

x1=zeros([size(A,1)*size(A,2) 1]);
x2=zeros([size(A,2)*size(A,1) 1]);

%Specify the degree
deg=90;
%Change the image size
C=uint8(zeros([size(A,1) size(A,2) 3 ]));

m=1;
%Find the midpoint
midx=ceil((size(C,1)+1)/2);
midy=ceil((size(C,2)+1)/2);

for i=1:size(A,1)
i1=i-midx;
for j=1:size(A,2)
%convert from cartesian to polar
[t,r]=cart2pol(i1,j-midy);
%Convert to Cartesian Co-ordinates
[x,y]=pol2cart(t,r);
x1(m)=round(x+midx);
x2(m)=round(y+midy);

m=m+1;

end

end
%check whether the values are within the image size.
x1(find(x1 < 1))=1;
x2(find(x2 < 1))=1;

n=1;
for i=1:size(A,1)
for j=1:size(A,2)
C(x1(n),x2(n),:)=A(i,j,:);

n=n+1;
end

end
imshow(C);

I got holes in between when I rotated at 45 degrees. So I used ceil , floor  and round function  to convert the decimals into whole numbers.
 45 degrees
 210 degrees

NOTE: Here I didn't re-size the image. May be in another post, I will concentrate on both scaling and rotating.
Use Meshgrid to make rotation faster.

Faster Implementation: Image Rotation_part 2
Like "IMAGE PROCESSING" page

To God Be All Glory said...

When i rotate an image using imrotate I get a warning like.
Actually i need to rotate a given image and then extract the boundary from it.
Since this error comes am not able to proceed..
can you help

Warning: Image is too big to fit on screen; displaying at 67%

Ben Dichter said...

muktesh shah said...

I got some dots in my image when i used this code (image rotation without using imrotate function) so if possible try to post about it....
Image which i used is 'cameraman.tif'...

Ana Laura Cabrera Hernández said...

Como eliminar el fondo negro cuando giras la imagen con el imrotate

Bezynhah said...

when I rotate 10º for example, the image rotated has black points inside de objetc.
What is this?