# IMAGE PROCESSING

" Two roads diverged in a wood, and I,
I took the one less traveled by,
And that has made all the difference "-Robert Frost

### Number of occurrences in cell array

To find the number of occurrence of a string in an array:

Consider a cell array
c={'one';'two';'three';'nine';'five';'two';'six';'one'; 'two';'five';};

The number of times the string ‘one’ occurs in the array

sum(strcmp('one',c))

ans =

2

To find the number of occurrence of all the elements in the array:

%c={'one';'two';'three';'nine';'five';'two'; 'six';'one'; 'two';'five';}; %dim=1

c='one','one','two','two','three','three','three','four','five','six','five','five'};%dim=2;

dim=2;
%Initialize the 'cell_array'
cell_array=cell([2 size(c,dim)]);
display(c);
inc=1;
for i=1:size(c,dim)
%Compare the elements in the 'cell_array' with the elements in 'c'
if(strcmp(cell_array(1,:),c(i))==0)
%If the element is not present, then add it to 'cell_array'.
cell_array(1,inc)=c(i);
%Find the number of occurence of the element
num=   sum(strcmp(c(i),c));
cell_array(2,inc)=num2cell(num);
inc=inc+1;
else
%Delete if the element is already present in the 'cell_array'.
cell_array(:,inc)='';

end

end

display(cell_array);

The result shows the elements in the first row and the number of occurrences in the second row.
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